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document trignometric-ratios-and-identities-8
Q-2. Show that Solution: Let  (Note ) or or 2 sin2 cos2 = 3 sin - 4 sin3
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document trignometric-ratios-and-identities-7
Dumb Question:- How should I approach when I look such a question for first time ? Ans:- Look, here was the anle and so we observed that if some how
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document trignometric-ratios-and-identities-6
(10) If a triangle ABC show that - Solution:- Dr = sinA + sinB - sinC Similarly Nr = 4 L.H.S. =            (11) Prove that tanA + 2...
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document trignometric-ratios-and-identities-5
Conditional Identities. If A + B + C = 180o then . (i) sin 2A + sin 2B + sin 2c = 4sinA sin B sinC. Why ? A + B + C = 180o So, A + B = 180o - C sin(A + B) = sin C cos (A + B) = - cos C...
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document trignometric-ratios-and-identities-4
Some nice manipulations: 1) Why ? = cos2 sin2 2sin cos = 1
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document trignometric-ratios-and-identities-3
Math: Trignometry Chapter Trignometri Ratios multiples of an angle : 1) sin 2 = 2sin cos= why ? sin (A +B) = sin A cos B + cos A sin B Put A =
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document trignometric-ratios-and-identities-2
Math: Trignometry Chapter Illustration 2: Find the value of tan (10200) ? 10200 = 10 X 900 + 300 If lies in the IV th Quadrant. So, tan (10 X 900 + 300 ) = - tan 300 = - ...
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document trignometric-ratios-and-identities-1
Math: Trignometry Chapter The word trignometry is devided from 2 greek words (1) Trigonon and (2) Meetron Trignon means triangle and metron means measure So, is science of measuning...
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document solution-of-triangles-8
Hard Q-1: The
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document solution-of-triangles-7
Q-7: Solve
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document solution-of-triangles-6
Q-3: If p, q are perpendiculars from the angular points A and B of the DABC drawn to any line
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document solution-of-triangles-5
Illustration 9: Prove that centroid, orthocenter and circumcenter of a D are collinear and
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document solution-of-triangles-4
Illustration 6: If in the DABC, O is circumcenter and R is the
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document solution-of-triangles-3
Area of Triangle ABC:
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document solution-of-triangles-2
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document Solution Of Triangles - 1
Introduction Every triangle has 3 angles and 3 sides. Given any 3 quantities out of 3 angles and 3 sides (at least one of which is a side) are given then remaining 3 can be found
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